4x^2-3x=9-x

Solution for 4x^2-3x=9-x equation:

4x^2-3x=9-x

We move all terms to the left:

4x^2-3x-(9-x)=0

We add all the numbers together, and all the variables

4x^2-3x-(-1x+9)=0

We get rid of parentheses

4x^2-3x+1x-9=0

We add all the numbers together, and all the variables

4x^2-2x-9=0

a = 4; b = -2; c = -9;
Δ = b2-4ac
Δ = -22-4·4·(-9)
Δ = 148
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{148}=\sqrt{4*37}=\sqrt{4}*\sqrt{37}=2\sqrt{37}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{37}}{2*4}=\frac{2-2\sqrt{37}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{37}}{2*4}=\frac{2+2\sqrt{37}}{8}
$